Verified Answer :

Benjamin16

\(x^{2}+2x+4 \\ \\ \Delta=2^{2}-4*1*4=4-16=-12 \\ \\ \sqrt{\Delta}= \sqrt{-12}= \sqrt{-1}* \sqrt{12}=i2 \sqrt{3} \\ \\ x_{1}= \frac{-2-i2 \sqrt{3} }{2}=-1- i\sqrt{3} \\ \\ x_{2}= \frac{-2+i2 \sqrt{3} }{2}=-1+i \sqrt{3}\)

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