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NonaTrudillo
NonaTrudillo NonaTrudillo
  • 05-08-2015
  • Mathematics
Answered

1+cos(8x)=

A4cos(2x)
B2sin^2(4x) C.4sin(2x) D.2cos^(4x)

Verified Answer :

Julik
Julik Julik
  • 05-08-2015

\(cos^2(x)+sin^2(x)=1 \\ 1=cos^2(4x)+sin^2(4x) \\ \\ cos(2x)=cos^2(x)-sin^2(x) \\ cos(8x)=cos(4 \times 2x)=cos^2(4x)-sin^2(4x) \\ \\ \\ 1+cos(8x)=cos^2(4x)+sin^2(4x) +cos^2(4x)-sin^2(4x) \\ cos^2(4x)+cos^2(4x)=2cos^2(4x)\)

D.2cos^(4x)


Answer Link
Katarina4
Katarina4 Katarina4
  • 19-02-2020

Answer:

2Cos^2(4x)

Step-by-step explanation:

Apex

Answer Link

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