Solve by factoring:25X^2+5X-12=0
\(25x^2+5x-12=0 \\ 25x^2-15x+20x-12=0 \\ 5x(5x-3)+4(5x-3)=0 \\ (5x+4)(5x-3)=0 \\ 5x+4=0 \ \lor \ 5x-3=0 \\ 5x=-4 \ \lor \ 5x=3 \\ x=-\frac{4}{5} \ \lor \ x=\frac{3}{5} \\ \boxed{x=-\frac{4}{5} \hbox{ or } x=\frac{3}{5}}\)
solve your equation step-by-step.25x2+5x−12=0Factor left side of equation.(5x−3)(5x+4)=0Set factors equal to 0.5x−3=0 or 5x+4=0x=3/5 or x=−4/5
