Verified Answer :

Julik

\(\log_{b}(x^y)=y\log_b(x) \\ \log_a(x)= \frac{\log_b(x)}{\log_b(a)} \\ \\ 3(5^x)=48 \\ \frac{3(5^x)}{3} =\frac{48}{3} \\ 5^x=16 \\ 5^x=16\\ x=\log_516 \\ x=\log_5(2^4) \\ x=4\log_52\\ x= \frac{4\log2}{\log5}\)

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