\(n;\ n+2-two\ consecutive\ odd\ integers\\\
+(n+2)=68\
+n+2=68\\2n+2=68\ \ \ |subtract\ 2\ from\ both\ sides\\2n=66\ \ \ \ |divide\ both\ sides\ by\ 2\
=33\to n+2=35\\\\Your\ answer:\boxed{33\ and\ 35}\)
\(Other\ method:\\\\68:2=34\\\\first\ number:34-1=33\\second\ number:34+1=35\)