emilyreynaert1220
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The distances (y), in miles, of two cars from their starting points at certain times (x), in hours, are shown by the equations below:


Car A

y = 60x + 10


Car B

y = 40x + 70


After how many hours will the two cars be at the same distance from their starting point and what will that distance be?


A2 hours, 150 miles
B2 hours, 190 miles
C3 hours 150 miles
D3 hours, 190 miles

Verified Answer :

We can simply set the two equations equal to each other:

60x+10=40x+70

We subtract 40x+10 from both sides to get:

20x=60

Divide by 20 to find that x=3.  Substitute this back into either equation to find the amount of miles - using the first, 60*3+10=190, so the answer is D.

Answer:

The correct option is d.

Step-by-step explanation:

The distances (y), in miles, of two cars from their starting points at certain times (x), in hours, are shown by the equations

Car A:

\(y=60x+10\)             ... (1)

Car B:

\(y=40x+70\)            .... (2)

Equate equation (1) and (2), to find the hours after which the two cars be at the same distance from their starting point.

\(60x+10=40x+70\)

\(60x-40x=70-10\)

\(20x=60\)

\(x=3\)

The value of x is 3. It means after 3 hours two cars be at the same distance from their starting point.

Substitute x=3 in equation (1) to find the distance.

\(y=60(3)+10\)

\(y=180+10=190\)

The distance is 190 miles.

Therefore option d is correct.

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