Verified Answer :

\(\frac{x^{5/6}}{x^{1/6}}=x^ \frac{2}{3} = \sqrt[3]{x^2}\)

Julik

\(\frac{x^{ \frac{5}{6} }}{x^{ \frac{1}{6} }} =x^{\frac{5}{6}- \frac{1}{6} }=x^ \frac{4}{6} }}=x^ \frac{2}{3} = \sqrt[3]{x^2}\)

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