Shannon walked 1 2/3 miles on Wednesday and 2 3/5 miles on Thursday. What was the total distance, in miles,Shannon walked during those 2 days?
First, add the integers to get 3. Then, add 2/3 and 3/5 by converting them into fifteenths, for a total of 19/15, or 1 4/15. Add these together to get 4 4/15 miles.
The total distance Shannon walked during those 2 days is \(4\frac{4}{15}\) miles .
A number expressed as a quotient, in which a numerator is divided by a denominator. In a simple fraction, both are integers. A complex fraction has a fraction in the numerator or denominator. In a proper fraction, the numerator is less than the denominator.
According to the question
Shannon walked on Wednesday in fraction = \(1\frac{2}{3}\) miles
= \(\frac{5}{3}\) miles
Shannon walked on Thursday in fraction = \(2 \frac{3}{5}\) miles
= \(\frac{13}{5}\) miles
The total distance, in miles covered by Shannon during those 2 days
= Shannon walked on Wednesday + Shannon walked on Thursday
= \(\frac{5}{3}\) + \(\frac{13}{5}\)
Taking lcm of denominator 3 and 5 = 15
= \(\frac{25+39}{15}\)
= \(\frac{64}{15}\) miles
= \(4\frac{4}{15}\) miles
Hence, The total distance Shannon walked during those 2 days is \(4\frac{4}{15}\) miles .
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