Verified Answer :

naǫ

\(e(4)=4^2+6 \times 4+21=16+24+21=61 \\ \\ m(4)=8 \times 4=32 \\ \\ v(4)=31 \times 4=124\)

v(x) has the largest value when x=4.

JeanaShupp

Answer: \(v(x)=31x\)


Step-by-step explanation:

Given Functions: \(e(x)=x^2+6x+21\)

\(m(x)=8x\\\\v(x)=31x\)

At x=4

\(e(4)=(4)^2+6(4)+21\\=16+24+21=61\\\\m(4)=8(4)=32\\\\v(4)=31(4)=124\)

here we can see v(4) has the largest value of 124 at x=4 .

Therefore, \(v(x)=31x\) is the function which has the largest value at x=4.

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