Verified Answer :

Since3122015

\(2700=2200(r+1)^5\\\frac{27}{22}=(r+1)^5\\\sqrt[5]{\frac{27}{22}}=\sqrt[5]{(r+1)^5}\\\frac{27}{22}^\frac{1}{5}=r+1\\r=\frac{27}{22}^{0.2}-1\\r=1.0418-1\\r=0.0418\)

r = 0.0418

solve your equation step-by-step.

2700=2200(1+r)^5

Flip the equation.

2200(r+1)^5 = 2700

Divide both sides by 2200.

2200(r+1)^5 / 2200 = 2700 / 2200

(r+1)^5=27/22

Solve Exponent.

(r+1)^5=27/22

((r+1)5) ^1/5 = (27/22)^1/5 (Raise both sides to power)

r+1=1.041809

r+1−1=1.041809−1(Subtract 1 from both sides)

r = 0.041809

Check answers. (Plug them in to make sure they work.)

r = 0.041809 (Works in original equation)

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