Identify the 12th term of a geometric sequence where a1 = 8 and a6 = -8,192. 134,217,728 33,554,432 -33,554,432 -134,217,728
\(a_1=8 \\
a_6=-8192 \\ \\
a_n=a_1 \times r^{n-1} \\
-8192=8 \times r^{6-1} \\
\frac{-8192}{8}=r^5 \\
-1024=r^5 \\
\sqrt[5]{-1024}=r \\
r=-4 \\ \\
a_{12}=8 \times (-4)^{12-1}=8 \times (-4)^{11}=8 \times (-4194304)=-33554432\)
The 12th term of the sequence is -33,554,432.
Answer:
-33,554,432.
Step-by-step explanation:
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