Could someone please explain to me clearly how to work this out using quadratics?
Find the values of a, b, c, d and e that make this following equation true.
4\(x^{2}\)(x-2)(x+3)+3 = ax\(x^{4}\)+b\(x^{3}\)+c\(x^{2}\)+dx+e
Find the values of a, b, c, d and e that make this following equation true.
4\(x^{2}\)(x-2)(x+3)+3 = ax\(x^{4}\)+b\(x^{3}\)+c\(x^{2}\)+dx+e
