Verified Answer :

naǫ

\(10^x=0.1 \% \times 10^y \\ \\ 10^x=\frac{0.1}{100} \times 10^y \\ \\ 10^x=\frac{1}{1000} \times 10^y \\ \\ 10^x=\frac{10^y}{10^3} \\ \\ 10^x=10^{y-3} \\ \\ \log_{10} 10^x=\log_{10} 10^{y-3} \\ \\ x=y-3 \\ \\ y=x+3\)

The answer is B.

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