For this case we have the following expression:
"6 to the 2nd power ÷ 2(3) + 4"
Rewriting the expression in algebraic form we have:
\(\frac{6^2}{2(3)+4}\)
Rewriting the numerator we have:
\(\frac{36}{2(3)+4}\)
Rewriting the denominator we have:
\(\frac{36}{6+4}\)
\(\frac{36}{10}\)
\(\frac{18}{5}\)
Dividing both numbers we have:
\(\frac{18}{5} = 3.6\)
Answer:
The result of the given expression is:
\(\frac{6^2}{2(3)+4}=3.6\)