Hartshorne319
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Each month, a retail store awards a blue ribbon to its employee of the month. The probability that Chloe is the employee of the month is 29% in January and 49% in February. What is the probability that she is awarded a blue ribbon in both January and February?

Verified Answer :

emilymurdock12

1421 / 100 = 14.21% 

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InesWalston

Answer:

\(0.1421\ or\ 14.21\%\)

Step-by-step explanation:

The probability that Chloe is the employee of the month in January is 29% or 0.29

i.e \(P(J)=0.29\)

The probability that Chloe is the employee of the month in February is 49% or 0.49

i.e \(P(F)=0.49\)

As both of the events are independent, so

\(P(J\ and\ F)=P(J)\cdot P(F)\)

\(=0.29\times 0.49\)

\(=0.1421=14.21\%\)

Therefore, the probability that Chloe is awarded a blue ribbon in both January and February is 0.1421 or 14.21%

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