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Natasha's dorm room is shaped like a triangle. The college brochure says it has an area of 875 square feet. The room is 35 feet long. Determine the width of the room at it's widest point.

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Gladiwata


formula for the area of a triangle
A=1/2 bh
b(base)=width
h(height)=length
given
A=875 ft^2
h=35 ft

b/width=?

solution:
875 ft^2=1/2 b(35)
b=875^2÷50
b=50 ft

The width of the room is 50 feet.

We have a triangle shaped dorm room with the following specifications -

Area = 875 square feet

height = 35 feet

We have to calculate the height of this dorm.

What is the formula to find the area of a triangle?

The formula to calculate the area of triangle is -

A = \(\frac{1}{2} \times b\times h\)

We can solve the problem given to us using the above formula -

Substituting the values in the formula above -

b = \(\frac{2A}{h}\)

b = \(\frac{2\times875}{35}\)

b = 50 feet.

Hence, the width of the room is 50 feet.

To solve more questions on area of triangles visit the link below-

https://brainly.com/question/19305981

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