Verified Answer :

Domain:  expression under square root is greater or equal than zero.

x+3>0
x>-3

Then:

\(\sqrt{x+3}}+4=5 \qquad |-4 \\ \\ \sqrt{x+3}=1 \qquad |(...)^2 \\ \\ x+3=1 \\ \\ x=-2 \in D\)

So the answer is x=-2

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