We have 3 sections.
\(\sf~Red=\dfrac{11}{20}\)
\(\sf~Blue=\dfrac{6}{20}\)
So the entire spinner is divided into \(\sf20\) sections.
Since we only have 3 sections(red, blue, green) we can add red and blue, and subtract 1 or 20/20.
\(\sf\dfrac{11}{20}+\dfrac{6}{20}\rightarrow\dfrac{11+6}{20}\rightarrow\dfrac{17}{20}\)
Subtract:
\(\sf\dfrac{20}{20}-\dfrac{17}{20}=\boxed{\sf\dfrac{3}{20}}\)
So the probability that the arrow landing on a green-colored section is \(\sf\dfrac{3}{20}\).
