Verified Answer :

SchwarzschildRadius

So,

\(\frac{4}{x} + \frac{2x}{x - 1} + \frac{x + 3}{2x}\)

Look at all three denominators.
\(x, x - 1, 2x\)

Factor them completely.
\((x), (x - 1), (2)(x)\)

Putting them together, we would get the following:
\((2)(x)(x-1)\ or\ 2x^2 - 2x\)

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