\(4x^{3}+43x^2+30x\)
First in factoring, you must find out what is common in the whole equation
\(x(4x^2+43x+30)\)
Now, make 2 sets of parentheses and "split up" the rest of the equation
Try to experiment which numbers work out
We are not subtracting anything so both parentheses are positive
\(x(4x+3)(x+10)\)
Therefore, the factored version of \(4x^3+43^2+30x\) is
\(x(4x+3)(x+10)\)
