A system of equations is shown below: n = 3m + 6 n − 2m = 2 What is the solution, in the form (m, n), to the system of equations? (−4, −6) (−5, −9) (2, 6) (1, 8)
\(n=3m+6 \\ n-2m=2 \\ \\ \hbox{substitute 3m+6 for n in the second equation:} \\ 3m+6-2m=2 \\ m+6=2 \\ m=2-6 \\ m=-4 \\ \\ n=3m+6=3 \times (-4)+6=-12+6=-6 \\ \\ \boxed{(m,n)=(-4,-6)}\)
Answer:
\((-4,-6)\).
Step-by-step explanation:
We have been given a system of equations and we are asked to find the solution for given system of equations in the form (m,n).
\(n=3m+6...(1)\)
\(n-2m=2...(2)\)
We will use substitution method to solve linear equation. Upon substituting equation (10 in equation (2) we will get,
\(3m+6-2m=2\)
Combine like terms:
\(m+6=2\)
\(m+6-6=2-6\)
\(m=-4\)
Substituting \(m=-4\) in equation (2) we will get,
\(n-2\times -4=2\)
\(n+8=2\)
\(n+8-8=2-8\)
\(n=-6\)
Therefore, the solution for our given system of equation is \((-4,-6)\).