Q: \(\frac{cos\theta}{tan\theta.cot\theta}=?\)
A:
\(\frac{cos\theta}{tan\theta.cot\theta}=cos\theta\)
because... \(tan\theta.cot\theta=1\)
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Q: \(\frac{cos\theta}{tan\theta}.cot\theta=?\)
A:
\(\frac{cos\theta}{tan\theta}.cot\theta&= \\ \\ \frac{cos\theta}{\frac{sin\theta}{cos\theta}}.\frac{cos\theta}{sin\theta}&= \\ \\ \frac{cos^2\theta}{sin\theta}}.\frac{cos\theta}{sin\theta}&= \\ \\ \frac{cos^3\theta}{sin^2\theta}}&= cos^3\theta.cosec^2\theta\)
