Mr. Martin is giving a math test next period. The test, which is worth 100 points, has 29 problems. Each problem is worth either 5 points or 2 points. Write a system of equations that can be used to find how many problems of each point value are on the test.
x - the number of 5 points worth problems
y - the number of 2 points worth problems
The test has 29 problems.
\(x+y=29\)
The test is worth 100 points.
\(5x+2y=100\)
The system of equations:
\(x+y=29 \\
5x+2y=100\)
The solution:
\(x+y=29 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\times (-2) \\
5x+2y=100 \\ \\
-2x-2y=-58 \\
\underline{5x+2y=100 \ \ \ \ \ } \\
3x=42 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\div 3 \\
x=14 \\ \\
x+y=29 \\
14+y=29 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |-14 \\
y=15\)
There are 14 problems worth 5 points and 15 problems worth 2 points.
There are 14 problems worth 5 points and 15 problems worth 2 points.
A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.
Let x be the number of 5 points worth of problems
Let y be the number of 2 points worth problems
The test has 29 problems.
x + y = 29
The test is worth 100 points.
5x + 2y = 100
The solution are;
x + y = 29
Or
-2x -2y = -59
5x + 2y = 100
By solving we get,
3x = 42
x = 14
and
y = 15
Hence, There are 14 problems worth 5 points and 15 problems worth 2 points.
Learn more about equations here;
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