The equation of a line:
\(y=mx+b\)
m - the slope, b - the y-intercept
The slope is 1/3, so the equation of the line is \(y=\frac{1}{3}x+b\).
Plug the values (x,y)=(-6,5) of the point into the equation:
\(5=\frac{1}{3} \times (-6)+b \\
5=-2+b \\
5+2=b \\
b=7 \\ \\
\boxed{y=\frac{1}{3}x+7}\)
