e^(2x) — 3e^x + 2 = 0Solve for x
You can essentially treat this equation as a factorable quadratic, with the variable being \(e^x\):\(e^{2x} - 3e^x + 2 = 0\)\((e^x - 2)(e^x - 1) = 0\)\(e^x = 1, 2\)\(x = \ln 1, \ln 2 = 0, \ln 2\)
