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RitaHerauf201 RitaHerauf201
  • 10-07-2015
  • Mathematics
Answered

The equation of a circle whose center is at ( 4,0 ) and radius is length 2 ( square root ) 3

Verified Answer :

naǫ
naǫ naǫ
  • 10-07-2015

The equation of a circle:
\((x-h)^2+(y-k)^2=r^2\)
(h,k) - the coordinates of the center
r - the radius

The center is (4,0), the length of the radius is 2√3.
\((x-4)^2+(y-0)^2=(2\sqrt{3})^2 \\ \boxed{(x-4)^2+y^2=12}\)

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AL2006
AL2006 AL2006
  • 10-07-2015


The equation of such a circle, described as
set forth in the question, is

                                         (x-4)² + y² = 12        .


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