Answer:
76
Step-by-step explanation:
The discriminant of the quadratic equation \(ax^2+bx+c=0\) is given by
\(D=b^2-4ac\)
The given equation is
\(3x^2-10x=-2\\\\3x^2-10x+2\)
Here, a = 3, b = -10 and c = 2
Therefore, discriminant is given by
\(D=(-10)^2-4(3)(2)\\\\D=100-24\\\\D=76\)
Therefore, the discriminant of the given equation is 76.