Verified Answer :

Way 1

3x^2x = -2

3x^2 - 10x + 2 = 0

Δ= (-10)^2 - 4 3 2 = 100 - 24 = 76


√Δ = 2√19

x1 = (10 - 2√19)/6 = (5 - √19)/3

x2 = (10 + 2√19)/6 = (5 + √19)/3

Answer:

76

Step-by-step explanation:

The discriminant of the quadratic equation \(ax^2+bx+c=0\) is given by

\(D=b^2-4ac\)

The given equation is

\(3x^2-10x=-2\\\\3x^2-10x+2\)

Here, a = 3, b = -10 and c = 2

Therefore, discriminant is given by

\(D=(-10)^2-4(3)(2)\\\\D=100-24\\\\D=76\)

Therefore, the discriminant of the given equation is 76.