First we have to find \(\Delta\) from the equation \(b^{2} -4ac\) where a, b and c are consecutive coefficients of the equation. In this case: \(a=1, b=4, c=-6\)
\(\Delta =4^2-4*(-6)=16+24=40\),
Later we will need to use \(\sqrt{\Delta}\) sofor us \(\sqrt{40}\). It can be then simplified to \(2 \sqrt{10}\).
Then we use quadratic formula \(x=\frac{-b\pm \sqrt{\Delta} }{2a}\) to see what are the options for x.
\(x=\frac{-4\pm 2\sqrt{10}}{2}\)
\(x=- 2 \pm \sqrt{10}\)
The answer for your question:
\(x=- 2 + \sqrt{10}\) or \(x=- 2 - \sqrt{10}\)
