Verified Answer :

blanchellite

\(a^{-n} = \frac{1}{ a^{n} }\)
So, \(4-2( 4^{-2})=4-2 \frac{1}{ 4^{2} } = 4-2 \frac{1}{16} = 4- \frac{1}{8}\)
We amplify 4 with 8 and we get:
\(\frac{32-1}{8} = \frac{31}{8}= 3,875\)

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