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MelidaMarean739
MelidaMarean739 MelidaMarean739
  • 30-06-2015
  • Mathematics
Answered

a train goes forward at a speed of 1m/s for 20 seconds then it stops and goes backward at a speed of 0.5 m/s for 4 sec after both movements are completed how far is the train located from its starting point notewe are asking for the trains final location not the total distance traveled

Verified Answer :

QuantumMechanic QuantumMechanic
  • 03-07-2015

1m/s20s = 20m forward
0.5m/s backward = -0.5m/s forward
20m+(-0.5m/s
4s) = 20m-2m = 18m forward

Or it goes forward 120 = 20m
then goes backward 0.5
4 = 2m
20-2=18m

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