Answered

How many mL of .1250 M KCl solution contains 2.330g of KCl? KCl = 74.55 amu

A250 mL
B26.95 mL
C25 mL

what do you do with the amu?

Verified Answer :

lulu1991

The amu is a unit which means the mass per neutron, So the 74.55 means the mass per mole KCl. So the mole number of 2.330g KCl is 2.330/74.55=0.031 mol. The volume is 0.031/0.1250=0.248 L ≈ 250 mL. So the answer is a.

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