Verified Answer :

Beanie4185

If the quadratic is a perfect square, then there has to be a way to write the quadratic as \((x - r)^2\), where \(r\) is a root of the equation. Expanding it out, we see that

\((x - r)^2 = x^2 - 2rx + r^2\)

Now let's compare this form to the one that we were given. Since \(r^2\) matches up with \(36\), \(r\) has to equal either \(6\) or \(-6\). So, since \(kx\) in the original equation matches up with \(-2rx\) in the equation we found, \(k = -2r\) and

\(\bf k = -12\) or \(\bf 12\)


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