Verified Answer :

ayah1

Lets see:

\(\frac{3}{8} + \frac{3}{8} + \frac{3}{8} = \frac{9}{8} = 1\frac{1}{8}\)  which is more than 1, but....

\(\frac{3}{8} + \frac{3}{8} = \frac{6}{8}\) 

The answer is 2 

\(1= \frac{8}{8}\)

\(\frac{8}{8} - \frac{6}{8} = \frac{2}{8}\)



The answer is 2 with a remainder of 2/8 or 1/4 or 0.25

The number of 3/8's that are in 1 is \(2\frac{2}{3}\)

From the question,

We are to determine the number of 3/8's that are in 1.

To do this, we will divide 1 by 3/8

The division operation is carried out as shown below

\(1 \div \frac{3}{8}\)

This becomes

\(1 \times \frac{8}{3}\)

= \(\frac{8}{3}\)

= \(2\frac{2}{3}\)

Hence, the number of 3/8's that are in 1 is \(2\frac{2}{3}\)

Learn more here: https://brainly.com/question/9145170

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