Verified Answer :

geerky42

x=0 is trivial solution. (since all terms have variable x)

Now divide both sides by x, you have 5x = -125

Now divide both sides by 5;

x = -125/5 = -25

So answer is x = 0 or -25.

TSO

\(\sf 5 x^{2} =-125x\)

Divide x on both sides

\(\sf\frac{5 x^{2} }{x} = \frac{-125x}{x}\)

Simplify that

\(\sf 5x=-125\)

Divide by 5 on both sides

\(\sf\frac{5x}{5} = \frac{-125}{5}\)

Simplify that

\(\sf x=-5\)

One of your final answer will be:

\(\bf{\huge{\boxed{x=-5}}}\)

But if you notice, we have x on both sides and it is doing multiplication. So another answer would be:

\(\bf{\huge{\boxed{x=0}}}\)

And so your two answers are:

\(\bf{\huge{\boxed{x=0,-5}}}\)

Related Questions