The equation of the unit circle:
\(x^2+y^2=1\)
\((x,y)=(x, \frac{\sqrt{3}}{3}) \\ \\
x^2+(\frac{\sqrt{3}}{3})^2=1 \\
x^2+\frac{3}{9}=1 \\
x^2+\frac{1}{3}=1 \\
x^2=1-\frac{1}{3} \\
x^2=\frac{3}{3}-\frac{1}{3} \\
x^2=\frac{2}{3} \\
x=\pm \sqrt{\frac{2}{3}} \\
x=\pm \frac{\sqrt{2}}{\sqrt{3}} \\
x=\pm \frac{\sqrt{2} \times \sqrt{3}}{\sqrt{3} \times \sqrt{3}} \\
x=\pm \frac{\sqrt{6}}{3}\)
x is equal to \(-\frac{\sqrt{6}}{3}\) or \(\frac{\sqrt{6}}{3}\).
