Answer: The correct answer is Option c.
Explanation:
To calculate the number of moles, we use the equation:
\(\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\) .....(1)
Given mass of hydrogen gas = 10.0 g
Molar mass of hydrogen gas = 2 g/mol
Putting values in equation 1, we get:
\(\text{Moles of hydrogen gas}=\frac{10.0g}{2g/mol}=5.0mol\)
The given chemical equation follows:
\(N_2+3H_2\rightarrow 2NH_3\)
As, nitrogen gas is present in excess. It is considered as an excess reagent.
Hydrogen gas is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
3 moles of hydrogen gas produces 2 moles of ammonia
So, 5.0 moles of hydrogen gas will produce = \(\frac{2}{3}\times 5.0=3.33mol\) of ammonia
Now, calculating the mass of ammonia by using equation 1, we get:
Molar mass of ammonia = 17 g/mol
Moles of ammonia = 3.33 moles
Putting values in equation 1, we get:
\(3.33mol=\frac{\text{Mass of ammonia}}{17g/mol}\\\\\text{Mass of ammonia}=(3.33mol\times 17g/mol)=56.3g\)
Hence, the correct answer is Option c.
