\(y=x^2+3x-6\)
Plug the values (x,y) into the equation and check if they satisfy it.
\(1. (-6,12) \\
12=(-6)^2+3 \times (-6)-6 \\
12=36-18-6 \\
12=12 \\
true \\ \\
2. (-4,-2) \\
-2=(-4)^2+3 \times (-4)-6 \\
-2=16-12-6 \\
-2=-2 \\
true\)
\(3. (2,4) \\
4=2^2+3 \times 2-6 \\
4=4+6-6 \\
4=4 \\
true \\ \\
4. (3,-6) \\
-6=3^2+3 \times 3-6 \\
-6=9+9-6 \\
-6=12 \\
not \ true\)
The answer is (4).
