To determine the pressure of 5.0 moles of nitrogen gas in a 2.0-liter container at a temperature of 268 K, given the universal gas constant 0.0821 L-atm/(mol·K), we use the Ideal Gas Law:
\(\[ PV = nRT \]\)
Where:
- \(\( P \)\) is the pressure in atmospheres (atm)
- \(\( V \)\) is the volume in liters (L)
- \(\( n \)\) is the number of moles (mol)
- \(\( R \)\) is the universal gas constant, 0.0821 L-atm/(mol·K)
- \(\( T \)\) is the temperature in Kelvin (K)
Rearrange the equation to solve for pressure \(\( P \)\):
\(\[ P = \frac{nRT}{V} \]\)
Substitute the given values into the equation:
\(\[ P = \frac{(5.0 \, \text{mol}) \times (0.0821 \, \text{L-atm/mol-K}) \times (268 \, \text{K})}{2.0 \, \text{L}} \]\)
Now, perform the multiplication and division:
\(\[ P = \frac{5.0 \times 0.0821 \times 268}{2.0} \]\)
\(\[ P = \frac{110.014}{2.0} \]\)
\(\[ P = 55.007 \, \text{atm} \]\)
Therefore, the pressure of the nitrogen gas in the container is \(\( 55.007 \, \text{atm} \)\). When rounded to two significant figures, the result is:
\(\[ P \approx 55 \, \text{atm} \]\)
Thus, the correct answer is:
D. 55 atm
