Answer:
\(\frac{1}{5}\)
Step-by-step explanation:
Using the properties of exponents / radicals
• \((a^m)^{n}\) = \(a^{mn}\)
• \(a^{-m}\) = \(\frac{1}{a^{m} }\)
• \(a^{\frac{1}{2} }\) = \(\sqrt{a}\)
given
\((25^{-\frac{3}{2}) } ^{\frac{1}{3} }\)
= \(25^{-\frac{3}{2} } ^{(\frac{1}{3}) }\)
= \(25^{-\frac{1}{2} }\)
= \(\frac{1}{25^{\frac{1}{2} } }\)
= \(\frac{1}{\sqrt{25} }\)
= \(\frac{1}{5}\)
