Answered

(1st write the formula, 2nd input the numbers, 3rd do the math).
SHOW WORK in the space.
A. A gas has a volume of 4 mL at a temp of 2 K. What would the temp be if the volume increased
to 10 mL?
Formula:
Input numbers:
Answer:

Verified Answer :

GinnyAnswer

Sure! Let's solve this step-by-step.

### A. A gas has a volume of 4 mL at a temperature of 2 K. What would the temperature be if the volume increased to 10 mL?

#### Formula:
We will use Charles's Law, which states:
\(\[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \]\)

Where:
- \(\( V_1 \)\) is the initial volume
- \(\( T_1 \)\) is the initial temperature
- \(\( V_2 \)\) is the final volume
- \(\( T_2 \)\) is the final temperature

We need to solve for \(\( T_2 \)\). Rearrange the formula to isolate \(\( T_2 \)\):
\(\[ T_2 = \frac{V_2 \cdot T_1}{V_1} \]\)

#### Input numbers:
Now, we substitute the given values into the formula:
- \(\( V_1 = 4 \)\) mL
- \(\( T_1 = 2 \)\) K
- \(\( V_2 = 10 \)\) mL

So,
\(\[ T_2 = \frac{10 \, \text{mL} \cdot 2 \, \text{K}}{4 \, \text{mL}} \]\)

#### Answer:
Now, perform the math:
\(\[ T_2 = \frac{10 \times 2}{4} \]\)
\(\[ T_2 = \frac{20}{4} \]\)
\(\[ T_2 = 5 \]\)

So, the temperature would be 5 K if the volume increased to 10 mL.

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