Answer: Answer below
1. Make improper fractions:
\(\frac{3 * 6 + 1}{6} + x = \frac{19}{42} =
\\ \\ \\
\frac{19}{6} + x = \frac{19}{42} =
\\ \\ \\
x = \frac{19}{42} - \frac{19 * 7}{6 * 7} =
\\ \\ \\
x = \frac{19}{42} - \frac{133}{42} =
\\ \\ \\
x = \frac{-114 : 2}{42 : 2} = -\frac{57 : 3}{21 : 3} = -\frac{19}{7} = -2\frac{5}{7}\)
So this is the answer. Hope this helps!