To determine the resistance of an automobile headlight given that a current of 2.50 amperes (A) flows through it when a voltage of 12.0 volts (V) is applied, we can use Ohm's Law. Ohm's Law states that the voltage (V) across a resistor is equal to the product of the current (I) flowing through it and its resistance (R). This can be formulated as:
\(\[ V = I \times R \]\)
To solve for resistance (R), we rearrange the formula:
\(\[ R = \frac{V}{I} \]\)
Let's plug in the given values:
- Voltage, \(\( V = 12.0 \)\) volts
- Current, \(\( I = 2.50 \)\) amperes
Now, substitute these values into the rearranged formula:
\(\[ R = \frac{12.0 \text{ V}}{2.50 \text{ A}} \]\)
Carrying out the division:
\(\[ R = 4.8 \text{ ohms} \]\)
Therefore, the resistance of the automobile headlight is \(\( 4.8 \)\) ohms.
