To determine the probability that a randomly selected candy from Daniel's bag will NOT be blue or orange, we can follow these steps:
1. Total Number of Candies:
- Daniel has a total of 32 candy-coated chocolates.
2. Count of Blue Candies:
- There are 11 blue candies in the bag.
3. Count of Orange Candies:
- There are 10 orange candies in the bag.
4. Count of Blue or Orange Candies:
- To find the total number of candies that are either blue or orange, we add the blue candies and orange candies together.
- Blue candies + Orange candies = 11 + 10 = 21
5. Count of Candies that are Neither Blue nor Orange:
- To find the number of candies that are neither blue nor orange, we subtract the number of blue or orange candies from the total number of candies.
- Total candies - Blue or Orange candies = 32 - 21 = 11
6. Determine the Probability:
- The probability of selecting a candy that is NOT blue or orange is the ratio of the number of candies that are neither blue nor orange to the total number of candies.
- Probability = (Number of candies that are neither blue nor orange) / (Total number of candies)
- Probability = 11 / 32
Thus, the probability that the candy Daniel selects is NOT blue or orange is \(\(\frac{11}{32}\)\).
The correct option is:
d) \(\(\frac{11}{32}\)\)
