Let's analyze each pair one by one to determine which pair of numbers has a sum of 100.
Option A: 32 and 58
\(\[ 32 + 58 = 90 \]\)
The sum is 90, which is not 100.
Option B: 32 and 68
\(\[ 32 + 68 = 100 \]\)
The sum is 100.
Option C: 42 and 68
\(\[ 42 + 68 = 110 \]\)
The sum is 110, which is not 100.
Option D: 52 and 58
\(\[ 52 + 58 = 110 \]\)
The sum is 110, which is not 100.
After evaluating all the options, we see that only Option B (32 and 68) results in a sum of 100.
So, the correct answer is:
B. 32, 68
