2NaCl + H2SO4 --> 2HCl + Na2SO4

How many grams of HCl can be prepared from 2.00 mol H2SO4 and 2.56 mol NaCl?

A7.30 g
B93.3 g
C146 g
D150 g
E196 g

Verified Answer :

\(\frac{2.00}1=2.00,\frac{2.56}{2}=1.28<2.00\) hence NaCl is the limiting reagant.

One mole of NaCl yields one mole of HCl, hence we'll make at most \(2.56*(1.00+35.5)=93.4g\)

That would be answer B (the difference probably comes from the molar mass of Cl that I chose, 35.5, whereas some prefer to take 35.4)