Answered

How many grams of lead would you expect to be left over if 18 g 1
of lead was mixed with 1.56 g of Sulfur?
19.56
11.56
1.44
○ 8.00
18.00
16.44

Verified Answer :

GinnyAnswer

Sure, let's solve this problem step by step.

1. Identify the initial amounts: We start with 18 grams of lead and 1.56 grams of sulfur.

2. Determine the total mass of the mixture: When we mix these two substances together, we get a total mass of:
\(\[ 18 \text{ grams (lead)} + 1.56 \text{ grams (sulfur)} = 19.56 \text{ grams} \]\)

3. Determine the lead left over: To find out how much lead is left over after mixing it with sulfur, we consider the initial mass of lead and subtract the mass of sulfur from the total mass. This gives us:
\(\[ 19.56 \text{ grams (total mass)} - 1.56 \text{ grams (sulfur)} = 18.00 \text{ grams} \]\)

So, the number of grams of lead that would be left over is 18.00 grams.

Therefore, the correct answer is:
18.00 grams.

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