What is the kinetic energy of a golf ball weighing 0.18 kg and travelling at 48.7 m/s? Note 1: If rounding is required, please express your answer as a number rounded to 2 decimal places. Note 2: The units are not required to be included in your answer in this instance.

To find the kinetic energy of a golf ball given its mass and velocity, we will use the kinetic energy formula and ensure our final answer is rounded to two decimal places.

\(\boxed{ \begin{array}{ccc} \text{\underline{Kinetic Energy:}} \\\\ K = \dfrac{1}{2}mv^2 \\\\ \text{Where:} \\ \bullet \ K \ \text{is the kinetic energy} \\ \bullet \ m \ \text{is the mass of the object} \\ \bullet \ v \ \text{is the velocity of the object} \end{array}}\)

\(\Longrightarrow K = \dfrac{1}{2}(0.18 \text{ kg})(48.7 \text{ m/s\\})^2\\\\\\\\\therefore K \approx \boxed{ 213.45 \text{ J}}\)

Thus, the kinetic energy of the golf ball is 213.45 joules, rounded to two decimal places.

Srivastava Srivastava · Answer 2 · 2024-05-30T01:30:34-04:00

The kinetic energy of a 0.18 kg golf ball travelling at 48.7 m/s is calculated to be approximately 213.45 J using the kinetic energy formula KE = (1/2)mv².

To find the kinetic energy (KE) of the golf ball, we use the formula:

KE = (1/2)mv²

where m is the mass and v is the velocity.

Given:

m = 0.18 kg
v = 48.7 m/s

Substitute the values into the formula:

KE = (1/2) 0.18 kg (48.7 m/s)²

KE = 0.09 * 2371.69

KE ≈ 213.45 J

Therefore, the kinetic energy of the golf ball is approximately 213.45 J.