A town has a population of 10000 and grows at 5% every year. What will
be the population after 5 years, to the nearest whole number?
Answer Attempt 2 out of 2
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Verified Answer :

To determine the population of a town after 5 years, given an initial population of 10,000 and an annual growth rate of 5%, we use the concept of exponential growth. Here's a step-by-step explanation of the solution:

1. Identify the initial population and growth rate:
- Initial population (\(\( P_0 \)\)): 10,000
- Annual growth rate (\(\( r \)\)): 5% or 0.05 (as a decimal)

2. Determine the number of years the population grows:
- Number of years (\(\( t \)\)): 5

3. Formula for exponential growth:
The population after \(\( t \)\) years can be calculated using the compound interest formula:
\(\[ P(t) = P_0 \times (1 + r)^t \]\)
where:
- \(\( P(t) \)\) is the population after \(\( t \)\) years
- \(\( P_0 \)\) is the initial population
- \(\( r \)\) is the growth rate
- \(\( t \)\) is the number of years

4. Substitute the given values into the formula:
\(\[ P(5) = 10000 \times (1 + 0.05)^5 \]\)
\(\[ P(5) = 10000 \times (1.05)^5 \]\)

5. Calculate \(\( (1.05)^5 \)\):
\(\[ (1.05)^5 = 1.2762815625 \]\)

6. Multiply the initial population by the growth factor:
\(\[ P(5) = 10000 \times 1.2762815625 \]\)
\(\[ P(5) = 12762.815625 \]\)

7. Round the population to the nearest whole number:
\(\[ P(5) \approx 12763 \]\)

Thus, the population of the town after 5 years, rounded to the nearest whole number, will be 12,763.