Sure, let's analyze this step by step.
When we toss a single coin, there are two possible outcomes: heads (H) or tails (T). Therefore:
- Tossing 1 coin results in \(\(2\)\) possible outcomes.
When we toss more coins, we need to consider the combinations of outcomes for all coins. Specifically:
- Tossing 2 coins results in \(\(2 \times 2 = 4\)\) possible outcomes (HH, HT, TH, TT).
The number of possible outcomes is given by \(\(2^n\)\), where \(\(n\)\) is the number of coins. So, for 6 coins, the total number of possible outcomes is:
\(\[
2^6
\]\)
Calculating this, we get:
\(\[
2^6 = 64
\]\)
So, if six coins are tossed simultaneously, the number of possible events (outcomes) is \(\(64\)\).
Therefore, the correct answer is:
A. 64
