Be sure to use proper Word Problem format for the following problems.
4. International basketball competitions are played on a rectangular court where the
length is 2m less than twice the width. If the perimeter of the court is 86m, what are the
dimensions of the court?

Verified Answer :

Certainly! Let's solve the word problem step-by-step.

### Problem
International basketball competitions are played on a rectangular court where:
- The length of the court is 2 meters less than twice the width.
- The perimeter of the court is 86 meters.

We are to find the dimensions (length and width) of the court.

### Step-by-Step Solution

1. Define Variables:
Let \(\( w \)\) be the width of the court in meters.
Let \(\( l \)\) be the length of the court in meters.

2. Translate the Problem Conditions into Equations:

- According to the problem, the length \(\( l \)\) is 2 meters less than twice the width:
\(\[ l = 2w - 2 \]\)

- The perimeter of a rectangle is given by the formula:
\(\[ \text{Perimeter} = 2 \times (\text{length} + \text{width}) \]\)

- The perimeter of the court is given as 86 meters:
\(\[ 2(l + w) = 86 \]\)

3. Substitute the Expression for the Length into the Perimeter Equation:
- Using the equation \(\( l = 2w - 2 \)\), substitute \(\( l \)\) into the perimeter equation:
\(\[ 2((2w - 2) + w) = 86 \]\)

4. Simplify and Solve for \(\( w \)\):
\(\[ 2(2w - 2 + w) = 86 \]\)
\(\[ 2(3w - 2) = 86 \]\)
\(\[ 6w - 4 = 43 \]\)
\(\[ 6w = 45 \]\)
\(\[ w = 7.5 \]\)

So, the width \(\( w \)\) of the court is 7.5 meters.

5. Find the Length \(\( l \)\):
- Substitute \(\( w = 7.5 \)\) back into the expression for the length:
\(\[ l = 2w - 2 \]\)
\(\[ l = 2(7.5) - 2 \]\)
\(\[ l = 15 - 2 \]\)
\(\[ l = 13 \]\)

So, the length \(\( l \)\) of the court is 13 meters.

### Conclusion:
The dimensions of the basketball court are:
- Width: 7.5 meters
- Length: 13 meters